[最も共有された！ √] p(x)=kx^2-3x+k 231603-P(x)=kx^2-3x+k
Namely, everywhere that the original formula has an " x ", I will now plug in an " x h "The polynomials `P(x)=kx^(3)3x^23and Q(x)=2x^(3)5xk,` when divided by `(x4)` leave the same remainder The value of k isNote in passing that P(X > k) = (1−p)k, k ≥ 0 Remark 13 As a variation on the geometric, if we change X to denote the number of failures before the first success, and denote this by Y, then (since the first flip might be a success yielding no failures at all), the pmf becomes
Find The Value Of K If X 1 Is A Factor Of P X In Each Of The Following Cases P X X2 X K Youtube
P(x)=kx^2-3x+k
P(x)=kx^2-3x+k-When p(x)= x^3 3x^2 kx 2 is divided by x2, the remainder is 4 What is the value of k?Given that (x2) has a remainder of 10, we can also say that when x = 2, P(x) = 10 We know this as it is stated in the Polynomial remainder theorem Using this information we can plug in 2 where there exists x's in our function and we can set that equal to 10 P(x) = x^43x^2kx2;
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I know I have to divide by x2 but I don't know how to do so or what to do after thatI'm not quite sure how to go about this If someone could give me some clues I could probably figure it outClick here👆to get an answer to your question ️ If the roots of x^3 3x^2 kx 3 = 0 are in AP then k =
Clearly , the roots of the given equation is real as already mentioned in the question , So , obviously the discriminant will be >= 0 for this quadratic equation , where equality holds iff the roots are equal , which is true in this case , hence dWelcome to Sarthaks eConnect A unique platform where students can interact with teachers/experts/students to get solutions to their queriesQuestion 3 Find the value of k, if x – 1 is a factor of p(x) in each of the following cases (i) p(x) = x 2 x k (ii) p(x) = 2x 2 kx √2 (iii) p(x) = kx 2 – 2x 1 (iv) p(x) = kx 2 – 3x k Solution (i) p(x) = x 2 x k Apply remainder theorem =>x 1 =0 => x = 1 According to remainder theorem p(1) = 0 we get
Favourite answer P X = 1 = k, P X = 2 = 2k P X=5 = 5k Probabilities add up to 1 so k 2k 3k 4k 5k = 1 So 15k = 1 giving k = 1/15 P X < 4 = P X = 1 or 2 or 3 = k 2k 3k = 6k = 6/15 or 2/5 E X = 1 x P X = 1 2xP X=2} 3xP X=3 4xP X=4 5xP X=5 { little x is times} This = k 4k 9k 16k 25k = 55k = 55/15 = 11/3A3x1 x1 C2x1 Dx1 polynomial long division \(6x^3 kx^2 x 2 x 2 = 6x^2kx 12x 2k25 \underbrace{\dfrac{4k52}{x2}}_{=0} \\ 6x^3 kx^2 x 2 x 2 = 6x^2kx 12x 2k25 0 \)But avoid Asking for help, clarification, or responding to other answers
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If the sum of the zeros of the quadratic polynomial kx^2 ‒ 3x 5 is 1, write the value of k asked Apr 10, in Polynomials by Vevek01 (472k points) polynomials;Graph g(x)=x Rewrite the function as an equation Use the slopeintercept form to find the slope and yintercept Tap for more steps The slopeintercept form is , where is the slope and is the yintercept Find the values of and using the form The slope of the line is the value of , and the yintercept is the value ofTo ask Unlimited Maths doubts download Doubtnut from https//googl/9WZjCW Find the value of k if `x1` is a factor of `p(x)``p(x)= kx^23xk`
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View Question When The Polynomial P X 3x 3 Kx 2 45x 25 Is Divided By X 5 The Remainder Is 0 Which Of The Following Is Also A Factor Of P X
P (x)= kx^23x2k Given alpha beta = alphabeta , then find the value of k and also roots of solution 2 See answers qwblues qwblues P(x) = kx²3x2k for the quadratic equation a=k, b= 3 , c=2k Let the roots alpha and beta be equal to x1 and x2 respectivelyChris has used the factor theorem1 The remainder theorem tells us that you get the same thing when you substitute 3 into a polynomial as you get when you divide the polynomial by x3 and take only the remainder 2 The factor theorem thell us that since x3 is a factor of the polynomial then if we divided the polynomial by x3, the remainder would be 0
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PX = 1 = k, PX = 2 = 2k PX=5 = 5k Probabilities add up to 1 so k 2k 3k 4k 5k = 1 So 15k = 1 giving k = 1/15 PX < 4 = PX = 1 or 2 or 3 = k 2k 3k = 6k = 6/15 or 2/5For what value of k is the polynomial p(x) = 2x3 – kx2 3x 10 exactly divisible by (x – 2) Mathematics Sum For what value of k is the polynomial p(x) = 2x 3 – kx 2 3x 10 exactly divisible by (x – 2)P(x) ax^2bxc Si b^24*a*c=0 El polinómio tiene solución única Entonces p(x) kx^23x1 3^24*k*1=0 94k=0 4k=9 k=9/4 k=225
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Find the value of k, if x – 1 is a factor of p(x) in the following case p(x) = kx^2 – 3x k CBSE Previous Year Question Paper With Solution for Class 12 Arts;Find the values of k for the quadratic equation kx(x2)6=0,so that it has two equal roots 2 See answers dharun1 dharun1 The given equation can be written in the form of now it has equal roots that means The Discriminant is 0 D = 0 Also Hence the value of K is 6 khushi khushiIf p(x) = x 32x 2 kx5 is divided by x2, the remainder is 11 find k hence find all the zeroes of x 3 kx 2 3x1 Share with your friends Share 10 Here is the link for the answer to a similar query https//www
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This is how much i have done it so far p (x)=kx^23xk p (1)=k (1)^23 (1)k =k3k =2k3 k=3/2 p (3/2)=3/2x^23x (3/2) p (x)=3/2x^23x3/2 p (1)= 3/2 (1)^2 3 (1) 3/2To ask Unlimited Maths doubts download Doubtnut from https//googl/9WZjCW The polynomials `P(x) = kx^3 3x^23` and `Q(x) = 2x^35x k`, when divided byQuestion 0318 Find k such that f(x)=x^3kx^2kx2 has the factor x2 I have no idea what this is and my final is due in a few hours!
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0 votes 1 answer If the sum of the zeros of the quadratic polynomial kx^2 3x 5 is 1 write the value of kA x 2 is a factor of P(x) C P(x) = 0, has two negative roots B 2 is root of P(x) = 0 D P(0) = – 2 1 See answer what the answer number with out solve brainlymomshie brainlymomshie PolynomialsCourse Title DMCC ALG002;
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EC02 Spring 06 HW5 Solutions February 21, 06 6 Problem 343 • X is an Erlang (n,λ) random variable with parameter λ = 1/3 and expected value EX =I know I have to divide by x2 but I don't know how to do so or what to do after thatThe Questions and Answers of Find the value of k such that 3x^2 2kx xk5 have the sum of zeros and as half of their product ?
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Welcome to Sarthaks eConnect A unique platform where students can interact with teachers/experts/students to get solutions to their queriesWhen the polynomial P(x) = 6x 3 kx 2 x − 2 is divided by x 2, the remainder is 0 Which of the following is also a factor of P(x)?K = 3/2 Explanation p(x) = kx²3xk If (x1) is a factor of p(x) then p(1) = 0 => k(1)²3×1 k = 0 => 2k 3 = 0 => 2k = 3 => k = 3/2 Therefore, Value of k = 3/2 ••••
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Transcript Ex 51, 29 Find the values of k so that the function f is continuous at the indicated point 𝑓(𝑥)={ (𝑘𝑥1, 𝑖𝑓 𝑥≤5@3𝑥−5, 𝑖𝑓 𝑥>5)┤ at x = 5 Given that function is continuous at 𝑥 =5 𝑓 is continuous at 𝑥 =5 If LHL = RHL = 𝑓(5) ie lim┬(x→5^− ) 𝑓(𝑥)=lim┬(x→5^ ) " " 𝑓(𝑥)= 𝑓(5) LHL at x → 5 (𝑙𝑖𝑚The Questions and Answers of Find the value of k such that 3x^2 2kx xk5 have the sum of zeros and as half of their product ?Given that f (x) = 3x 2 2x, find f (x h) This one feels wrong, because it's asking me to plug something that involves x in for the original x But this evaluation works exactly like all the others;
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What is the value of "k" when P(x)=x^3 3x^2 kx 2 is divided by x2 and the remainder is 4?If the sum of the zeros of the quadratic polynomial kx^2 ‒ 3x 5 is 1, write the value of k asked Apr 10, in Polynomials by Vevek01 (472k points) polynomials;When the polynomial P(x) = 3x^3 kx^2 45x 25 is divided by x 5, the remainder is 0 Which of the following is also a factor of P(x)?
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If p(x) = x 3 – 2x 2 kx 5 is divided by (x – 2), the remainder is 11 Find k Hence find all the zeroes of x 3 kx 2 3x 1 (12) Solution p(x) = x 3 – 2x 2 kx 5, When x – 2, p(2) = (2) 3 – 2(2) 2 k(2) 5 ⇒ 11 = 8 – 8 2k 5 ⇒ 11 – 5 = 2k ⇒ 6 = 2k ⇒ k = 3 Let q(x) = x 3 kx 2 3x 1 = x 3 3x 2 3xA continuous random variable with PDF f(x) = kx(1 x), 0 $\mathrm{\le}$ x $\mathrm{\le}$ 1 Find K and determine a number ab such that P(x $\mathrm{\le}$ b) = p(x $\mathrm{\ge}$ b)Graph g(x)=x Rewrite the function as an equation Use the slopeintercept form to find the slope and yintercept Tap for more steps The slopeintercept form is , where is the slope and is the yintercept Find the values of and using the form The slope of the line is the value of , and the yintercept is the value of
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X y = G What can QuickMath do?Are solved by group of students and teacher of Class 10, which is also the largest student community of Class 10Graph p(x)=(x2)(x2)(x3) Find the point at Tap for more steps Replace the variable with in the expression Simplify the result Tap for more steps Simplify each term Tap for more steps Raise to the power of Raise to the power of Multiply by Multiply by Simplify by adding and subtracting Tap for more steps
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CBSE Previous Year Question Paper With Solution for Class 12 CommerceThanks for contributing an answer to Mathematics Stack Exchange!P (x)= kx^23x2k Given alpha beta = alphabeta , then find the value of k and also roots of solution 2 See answers qwblues qwblues P(x) = kx²3x2k for the quadratic equation a=k, b= 3 , c=2k Let the roots alpha and beta be equal to x1 and x2 respectively
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Chris has used the factor theoremDivide k1, the coefficient of the x term, by 2 to get \frac{k1}{2} Then add the square of \frac{k1}{2} to both sides of the equation This step makes the left hand side of the equation a perfect squareClick here👆to get an answer to your question ️ When x^3 3x^2 kx 4 is divided by (x 2) , the remainder is 2k then the value of k is
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Question 0318 Find k such that f(x)=x^3kx^2kx2 has the factor x2 I have no idea what this is and my final is due in a few hours!This is how much i have done it so far p(x)=kx^23xk p(1)=k(1)^23(1)k =k3k =2k3 k=3/2 p(3/2)=3/2x^23x(3/2) p(x)=3/2x^23x3/2 p(1)= 3/2(1)^2 3(1) 3/2 = 3/233/2 = 6/23 = 0 therefore, (x1) is a factor of 3/2x^23x 3/2 after dividing 3/2x^2 3x 3/2 with x1 i got the quotient 3/2x 3/2 (remainder=0) which i can't middle term split so what did i do wrong that i amQuickMath will automatically answer the most common problems in algebra, equations and calculus faced by highschool and college students The algebra section allows you to expand, factor or simplify virtually any expression you choose It also has commands for splitting fractions into partial fractions
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When the polynomial P(x) = 3x^3 kx^2 45x 25 is divided by x 5, the remainder is 0 Which of the following is also a factor of P(x)?Are solved by group of students and teacher of Class 10, which is also the largest student community of Class 10Por tanto manos a la obra y dividamos los polinomios en cuesti on x3 kx 2 3x 1 Por tanto manos a la obra y dividamos los polinomios School Universidad de Santiago de Chile;
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The common root of x 2 − 5 x 6 = 0 and x 2 − 8 x 1 5 = 0 is the root of x 2 4 x q = 0 then value of q is View solution If 3 is a zero of polynomial 2 x 2 x k , then value of k will beIf x − 1 is a factor of polynomial p(x), then p(1) must be 0 p(x) = kx 2 − 3x k ⇒ p(1) = 0 ⇒ k(1) 2 − 3(1) k = 0 ⇒ k − 3 k = 0 ⇒ 2k − 3 = 0 ⇒ k = 3/2 Therefore, the value of k is 3/2Please be sure to answer the questionProvide details and share your research!
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If the sum of the zeros of the quadratic polynomial kx^2 ‒ 3x 5 is 1, write the value of k asked Apr 10, in Polynomials by Vevek01 (472k points) polynomials;Ex 24, 3Find the value of k, if x − 1 is a factor of p(x) in each of the following cases(i) p(x) = x2 x kFinding remainder when x2 x k is divided by x – 1Step 1 Put Divisor = 0x – 1 = 0 x = 1Step 2 Let p(x) = x2 x kPutting x = 1 p(1) = (1) (टीचू)Uploaded By SuperHumanField27 Pages 6 Dado el polinomio p (x) = x 4 k 2 x 2 kx 1
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